perform the following equation and simplify your answer?

Question

((24g-144)/(g^2-2g-24)) * ((g^2-3g-28)/(4g-28))

Answer 1

in first term (24g-144)/(g^2-2g-24)
take 24 common from numerator & factorize the denominator
= 24*(g-6)/[ (g+4)(g-6) ]
=24/(g+4) ..........................(g-6) cancels

in the second term ((g^2-3g-28)/(4g-28))
factorize numerator and take out 4 from denominator
=[ (g-7)(g+4) ]/[ 4*(g-7) ]
=(g+4)/4

now multiply both terms
=(24/4)
=6

Answer 2

=24(g-6)(g-7)(g+4) / 4(g+4)(g-7)(g-6)
=6