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((m^3+m)/(2) * ((4)/(m^2+m))

2007-07-23 03:19:21 · 2 answers · asked by whatever 1 in Science & Mathematics Mathematics

2 answers

=4m(m^2 + 1)/2m(m+1)
=2(m^2 + 1)/(m+1)

2007-07-23 03:24:12 · answer #1 · answered by gebobs 6 · 0 0

f(m) = (m^3 + m) / 2 * 4/(m^2 + m)
f(m) = m (m^2 + 1 ) * 4/2 * 1/ [m (m + 1)]
since m / m = 1, and 4/2 = 2,
f(m) = 2 (m^2 + 1) / (m+1)

2007-07-23 10:26:53 · answer #2 · answered by anobium625 6 · 0 0

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