The resistances of the primary and secondary coils of a transformer are 45 and 13 , respectively. Both coils are made from lengths of the same copper wire. The circular turns of each coil have the same diameter. Find the turns ratio Ns/Np.
2007-07-23 03:01:07 · 2 answers · asked by cwhughes13 2 in Science & Mathematics ➔ Physics
Since the winding turns are the same diameter in each winding, the number of turns in each winding is proportional to the lengths of the wires, which are proportional to the resistances (since the same wire is used). So the turns ratio Ns/Np is 13/45.
2007-07-23 03:16:45 · answer #1 · answered by kirchwey 7 · 1⤊ 0⤋
hi... shall we placed OHM's to artwork right here P=I x E if the voltage became one hundred on the 50 area the voltage on the200 area could be 4 hundred the x-former ratio being 4:a million the amps on the 50 area are 2(given) 100volts x2amps =2 hundred watts and the amps on the two hundred area could be equivalent to the comparable wattage or 4 hundred / .5 =2 hundred watts.. the ratio remains 4:a million .5 amp is the respond from the E
2016-10-22 10:14:35 · answer #2 · answered by matchett 4 · 0⤊ 0⤋