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explain the relationship between the horizontal velocity and the vertical velocity of a projectile fired into the air from a location on Earth's surface.?

a jogger runs one lap around a circular track that has a radius of 100 meters in 2.20 minutes. what will be her average velocity at the instant she recrosses the start-finish line?

2007-07-23 02:10:54 · 3 answers · asked by genesis 1 in Science & Mathematics Mathematics

3 answers

The horizontal velocity will remain constant provided that we ignore air resistance.
The vertical velocity will decrease from a maximum, when it is fired until it becomes = 0 at its highest point in the trajectory, from then it will start increasing again but in the opposite direction as the projectile starts its downward descent.

Her average velocity will be 0 because her total displacement will be 0.
Her average speed will be = total distance/ time
v = 2 x pi x 100/(2.2 x 60)
v = 4.76 m/s

2007-07-23 02:22:16 · answer #1 · answered by Southpaw 5 · 0 0

The horizontal and vertical velocities are independent. The vertical velocity is affected by gravitational acceleration. The horizontal velocity remains constant (if we ignore air resistance) while the object remains airborn, but then theoretically becomes zero when the object hits the ground. (In actuality, the object will bounce and roll a little further.)

Her average velocity will be 0 because she has zero net displacement at that moment. Average velocity is equal to net displacement divided by elapsed time. If there is no net displacement, regardless of path length traveled, the average velocity is zero.

2007-07-23 09:14:26 · answer #2 · answered by DavidK93 7 · 0 0

you probably would be better asking this question in the physics section.
When you throw a projectile, you can always break the forces into a horizontal and vertical component.
For the second question, the circumference of the track
C=2pi(100)=200pi meters
200pi meters/2.20 minutes

2007-07-23 09:17:11 · answer #3 · answered by leo 6 · 0 0

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