(3x + 4y)(x + y) =
3x² + 4xy + 3xy + 4y² =
Collecting like terms
3x² + 7xy + 4y²
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2007-07-22 23:06:28
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answer #1
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answered by SAMUEL D 7
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Use the FOIL method. Multiply the first (3x X x) then the outer (3x X y) next the inner (4y X x) and finally the last (4y X y). This will give you 3x^2 + 3xy + 4xy + 4y^2 and finally 3x^2+7xy+4y^2.
2007-07-23 03:43:01
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answer #2
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answered by Anonymous
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3x² + 3xy + 4xy + 4y² = 3x² + 7xy + 4y²
2007-07-23 03:42:43
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answer #3
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answered by Como 7
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(3x+4y) (x+y)
= 3x*x + 3x*y + 4y*x + 4y*y
= 3x^2 + 3xy + 4xy + 4y^2
= 3x^2 + 7xy +4y^2
2007-07-23 04:47:48
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answer #4
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answered by gab BB 6
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(3x+ 4y)(x+y)= 3*x^2 + 7*x*y+ 4*y^2
2007-07-23 05:05:19
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answer #5
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answered by Anonymous
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3x^2 + 7xy + 4y^2
2007-07-23 03:48:58
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answer #6
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answered by mramahmedmram 3
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(3x+4y)(x+y) = 3x^2+3xy+4xy+4y^2= 3x^2+7xy+4y^2
2007-07-23 04:15:26
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answer #7
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answered by teknique 6
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editing
3x(2) + 3xy + 4xy + 4y(2)
3x(2) + 7xy 4y(2)
(2) = squared
I showed you how to do it aswel so I deserve best answer
2007-07-23 03:36:00
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answer #8
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answered by Anonymous
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3x^2+7xy+4y^2
2007-07-23 04:50:59
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answer #9
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answered by koooooooooooool 2
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3x^2 + 7xy + 4y^2
this is the answer.
Multiply separately and simplify.
2007-07-23 03:36:41
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answer #10
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answered by Encyclopedia 4
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