A bubble with a volume of 1.0 cm^3 forms at the bottom of a lake that is 20.0 m deep. The temperature at the bottom of the lake is 10.0 degrees C. The bubble rises to the surface where the temperature is 25.0 degrees C. Assume that the bubble is small enough that its temperature always matches that of its surroundings.
2007-07-22 17:56:22 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
This homework problem was probably designed to illustrate the relationship PV=nRT. It's underdefined, because we don't know the air pressure at the surface of the water (as answer 1 pointed out), and the surface tension of the water, which adds to the internal pressure of the bubble, has been neglected. Since you've been given the surface temp as 25C, ignore the quibbles and solve the equation for STP at the water surface.
2007-07-22 18:26:46 · answer #1 · answered by virtualguy92107 7 · 0⤊ 0⤋
You need to figure out the value for the pressure of water at 20 meters deep...then use boyle's law to calculate the volume
2007-07-23 01:17:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
It depends on the altitude at which the bubble breaks the surface.
2007-07-23 01:03:51 · answer #3 · answered by Pinyon 7 · 0⤊ 0⤋