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A test rocket follows a parabolic path. Its path is followed by two tracking stations. A & B. On a grid system, the launch pad is at (0,0). The tracking stations are on the horizontal axis. Station A is 4.5 KM from the launch site and station B is 7 km from the launch site.

The tracking stations record two measurements: the first, station A records an angle of 78.2 degrees and station B records an angle of 67.4 degrees, the second places the rocket at the co-ordinates (10,20) on the parabola.

***Find the EQUATION of the flight path. Find how FAR from the launch site the rocket lands***

I need ALL the steps to finding this answer, I need it for tomorrow!!!

2007-07-22 15:49:23 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

assume the two stations are on one side of the launch pad

the equation that presents its path will be in the form of:
y = ax^2 + bx + c

but to find that equation, we must first use:
y = .5at^2 + Vt + Xi

let A be the position where the rocket is lauch.
Let B be the position where the rocket is tracked by the two stations.
Let C be where the station A is at
Let D be where the station B is at

From there, you should be able to draw a big triangle consist of two smaller triangle ABC and ABD.

Now draw an altitude from B to opposite side. Let's call E is a point where the altitude bisect the opposite side

From the given informations:
AC = 4.5km
AD = 7km

Let x be the length of AE, then 4.5 - x is the length of EC
and 7- x is the lenth of ED

lets call the altitude h

tan(78.2) = h/(4.5 - x)
tan(67.4) = h/(7 - x)

h = tan(78.2)(4.5 - x)
h = tan(67.4)(7 - x)


tan(78.2)(4.5 - x) = tan(67.4)(7 - x)
tan(78.2)4.5 - tan(78.2)x = tan(67.4)7 - tan(67.4)x
tan(78.2)4.5 - tan(67.4)7 = -tan(67.4)x+ tan(78.2)x
tan(78.2)4.5 - tan(67.4)7 = x (-tan(67.4)+ tan(78.2) )
x =( tan(78.2)4.5 - tan(67.4)7 ) / (-tan(67.4)+ tan(78.2) )
x = 1.9811

h = tan(78.2)(4.5 - x)
h = tan(78.2)(4.5 - 1.9811)
h = 12.0569km

So when the rocket is recorded, its altitude is 12.0569km

I can't go any further because there isn't enough information to find the origional speed other rocket. We need speed to plug in the equation y = .5at^2 + Vi +yi

2007-07-22 16:32:41 · answer #1 · answered by Ha!! 2 · 0 0

I think you should have copied and pasted the original question here. What we don't know is
# does (x,y)=(10,20) means when x=10km y=20km?
This conflicts with your statement that station B is 7km not 10km when the measurement was made. Does it mean that the measurements were made not directly overhead of stations A or B?
# If the measurements were not made directly overhead A or B, were they made simultaneously?

What I can guess is the question is an exercise of the geometric definition of a parabola,
A parabola is generated as the tangential locus of a line of constant length connecting the opposite points of another two lines placed at an angle of each other.
Resulting in an equi-ratio at any point of the parabola which is too difficult to describe without a drawing.

2007-07-22 16:40:42 · answer #2 · answered by miamidot 3 · 0 0

There is not enough information. Which SIDE of the launch pad are the two tracking stations on? Also, which side of the current location of the rocket are they on?

2007-07-22 15:56:03 · answer #3 · answered by Northstar 7 · 0 0

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