how do u solve equations like this?

Question

1)2p-3r +t for p=10 r=-4 and t=5

2)p^2-r^2 for p=10 r and t=5

Answer 1

An equation requires = sign so these are not equations.
These are expressions.
Question 1
2p - 3r + t
20 + 12 + 5
37

Question 2
p² - r²
(p - r) (p + r)
(10 - 5) (10 + 5)
5 x 15
75

Answer 2

( 2) ( 10 ) - ( 3 ) ( -4 ) + ( 5 ) = 20 +12 + 5 = 37

( 10 ) ^2 - ( 5 ) ^2 = 100 -25 = 75

You just substitute the given values into the equation and perform the arithmetic asked by the equation.

I hope this is helpful to you in learning this material.

Answer 3

substitute the values in place of the variables in the expressions

2(10) - 3(4) + 5 or 20 - 12 + 5 = 13

(10)^2 - (5)^2 = 100 - 25 = 75

Answer 4

you just plug in the numbers that are indicated for each letter.. for example ur first equation would be 2(10)-3(4)+5 which gives you 20-12+5..which is 8+5 which is 13

the second one would be 10^2-(u didnt out an r so i will just assume its 4) 4^2..and that gives u 100-16..which is 84

Answer 5

You just replace the letters with the numbers
2*10-3*-4+5=38
10r^2-r^2=100r^2-r^2=99r^2
I'm not sure about the second one though

Answer 6

1.
2*10-3*-4+5
20-(-12)+5
32+5
35

2.
10^2-(-4)^2
100+16
116

Answer 7

I solve them very well! How U solve 'em?

Answer 8

scsd