math problem?

Question

solve each of the following systems of linear inequalities graphically

3x - y < 6
x > 1
y<3

the greater and less signs has a line under them

Answer 1

3x-y=<6
-y =< 6-3x
y => 3x-6
Draw a line through the points (0,6) and (2,0). Shade everything above this line.

x >= 1
Draw a vertical line through (1,0).
Shade everything to the right of this line.

y=<3
Draw a horizontal line through (0,3)
Shade everything below this line.

Answer 2

Get a piece of paper (graph paper is best). Draw x and y axis on the paper, then a line for the equation y = 3x - 6 (I assume you know how to do this... slope of 3 and intersects y axis at y = -6.)

Then shade the area where 3x - y is less than six (it will be all of the area on one side of the line or the other).

Then draw a vertical line intesecting x = 1. Shade all of the area where x is larger than 1.

There will now be an area where two shaded regions overlap.

Draw a final line intersecting at y = 3 (horizontal). Shade all of the area where y is less than 3.

The solution is the area where all three shaded regions overlap, because any point in this area satisfies each condition in the system of inequalities. The result is some sort of triangular region.

Answer 3

I cant really graph it on yahoo answers...im sry!

Answer 4

graphically? how?!