write a quadratic equation given this solution?

Question

write a quadratic equation given this solution
-6,4

what do i do here....thanks for the help

Answer 1

There are three ways of writing a quadratic equation:

1: (x+6)(x-4)

2: x^2+2x-24, which you get by expanding the first way.

3: (x-p)^2+q

p = - b/2a = -1
q = (4ac-b^2)/4a = (-96-4)/4=-25

which gives us the third way:
(x-(-1))^2 - 25 = (x+1)^2 - 25

So there you are:

(x+6)(x-4)

x^2+2x-24

(x+1)^2 - 25

Answer 2

Working Backwards Method Based on the solutions, you know that x=-4 and x=1/3 Set them equal to 0 (x+4)(x-1/3)=0 then multiply them to form an equation x^2-1/3x+4x-4/3 simplify 0=x^2+3 2/3x-4/3 Sum and Product Method sum of -4 and 1/3=-3 2/3 product of -4 and 1/3=-4/3 to form the equation, it is 0=x^2 -sum x +product 0=x^2+3 2/3x-4/3

Answer 3

If this means that the roots are -6 and 4, the equation is simply (x+6)(x-4) = 0.

Answer 4

Let x be the variable:

y = (x + 6)(x - 4)

Since the answers are -6 and 4. Now, let's multiply out:

y = x^2 - 4x + 6x - 24
y = x^2 + 2x - 24

Answer 5

sum of the roots
= -6+4
= - 2
Product of the roots
= -6*4
=-24
Therefore,the equation is
x^2+2x-24=0

Answer 6

It would be x-(-6) times( x-4). Using the FOIL method, (multiply first ones, inner ones, outer ones, and last ones) you would get x^2 -4x +6x -24 which simplifies into x^2 +2x -24.

Answer 7

(x+6)= 0 so that x will be -6
x-4=0 so that x will be 4
so the factors are (x+6) and ( x-4)
(x+6)(x-4)=x^2-4x+6x-24
=x^2+2x-24

Answer 8

(x + 6) (x - 4) = 0
x² - 4x + 6x - 24 = 0
x² + 2x - 24 = 0

Answer 9

(x+6)(x-4)=0
x^2 -4x+6x-24=0
x^2+2x-24=0 (answer)