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In bridge, the 52 cards of a standard deck are dealt to four players. How many different ways are there to deal bridge hands to four players?

2007-07-22 11:28:54 · 4 answers · asked by TCM 3 in Science & Mathematics Mathematics

4 answers

C(52,13) * C(39,13) * C(26,13) * C(13,13)
= 52!/(13! * 39!) * 39!/(13! * 26!) * 26!/(13! * 13!) * 13!/(13! * 0!)
= 52!/13! * 1/(13! * 26!) * 26!/(13! * 13*)
= 52!/(13!)^4
= 53644737765488792839237440000
= 5.3 * 10^28 (approx)

2007-07-22 11:50:23 · answer #1 · answered by gudspeling 7 · 0 0

About 53644700000000000000000000000 ways.

2007-07-22 18:45:58 · answer #2 · answered by oregfiu 7 · 0 0

Hi. I think it may be 52! (52 factorial) -4!.

2007-07-22 18:33:43 · answer #3 · answered by Cirric 7 · 0 2

4 to the 52nd power.

2007-07-22 18:34:16 · answer #4 · answered by Anonymous · 0 2

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