= 5y - 3 - y + 2
= 4y - 1
2007-07-22 11:24:20
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answer #1
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answered by Como 7
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5y - 3 - y + 2
= 4 y -1
2007-07-21 19:53:02
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answer #2
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answered by CPUcate 6
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you must know first about combining similar terms:
so:
5y-3
- y -2
----------
that's the way to help you understand.
subtract 5y and y:
use law of subtracting integers
5y - y = 4y
then, -3 - (-2) = -3 + 2 = -1 becuase negative times negative is positive
then it becomes 4y -1
got it?
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2007-07-21 20:02:40
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answer #3
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answered by Anonymous
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5y-3-y+2 = 4y-1
2007-07-21 19:58:59
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answer #4
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answered by Anonymous
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5y -3 -y +2
= 4y -1
2007-07-21 19:52:37
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answer #5
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answered by ppp 1
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5y-3-y+2 = 4y-1
2007-07-21 19:52:21
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answer #6
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answered by Anonymous
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(5y-3)-(y-2) distribute the minus
5y-3-y+2
4y-1
2007-07-21 19:54:09
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answer #7
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answered by Lynn 4
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(5y - 3) - (y - 2) = 5y - 3 - y + 2
= 4y - 1
2007-07-21 21:18:16
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answer #8
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answered by Anonymous
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(5y - 3) - (y - 2) =
5y - 3 - y + 2 =
4y -1
2007-07-21 19:56:46
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answer #9
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answered by Anonymous
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(5y-3)-1(y-2) = (5y-3) - y + 2
= 4y - 1
2007-07-21 21:46:32
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answer #10
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answered by Anonymous
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