2007-07-21 16:48:48 · 4 answers · asked by jrseeg1rl 2 in Science & Mathematics ➔ Mathematics
9x^2-12xy+4y^2
=x^2-12xy+36y^2
(multiple the 1st number to the last 1 to make it jus x^2)
=9x^-6xy-6xy+4y^2
(find da two factors of 36 dat adds up to -12 for e.g -6*-6=36 then add it to the old equation where the -12xy was)
=3x(3x-2y)-2y(3x-2y)
=(3x-2y)(3x-2y)
Ans
=(3x-2y)^2
2007-07-21 17:11:02 · answer #1 · answered by Sexyv101 1 · 0⤊ 0⤋
9x^2-12xy +4y^2?
= (3x - 2y)(3x - 2y)
same as:
= (3x - 2y)^2
2007-07-21 23:55:14 · answer #2 · answered by Reese 4 · 0⤊ 0⤋
(3x - 2y)^2
Check:
(3x - 2y) * (3x - 2y) FOIL
9x^2 - 6xy - 6xy + 4y^2
9x^2 - 12xy + 4y^2
2007-07-21 23:59:40 · answer #3 · answered by Scott M 2 · 0⤊ 1⤋
(3X-2Y)(3X-2Y), OR (3X-2Y)^2
2007-07-21 23:57:09 · answer #4 · answered by Grampedo 7 · 0⤊ 0⤋