Find x if x+2, 3x-4, and 2x + 7 are in arithmetic progression?

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Find x if x+2, 3x-4, and 2x + 7 are in arithmetic progression?

2007-07-21 13:07:17 · 3 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics

3 answers

2(3x-4) = x+2 + 2x+7
6x-8 = 3x+9
x = 17/3
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Reason: For arithmetic progression, twice the middle term equals to the sum of the two neighbor terms.

2007-07-21 13:13:41 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

An arithmatic progression has equally spaced terms. The difference between adjacent terms is the same.

(3x - 4) - (x + 2) = (2x + 7) - (3x - 4)
2x - 6 = -x + 19
3x = 25
x = 25/3

2007-07-21 20:12:21 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋

very simple
let x+2 =a
3x-4=b
2x+7=c
in A.P. standered is
2b=a+c
2(3x-4)=(x+2)+(2x+7)
6x-8=3x+9
3x=17
x=17/3

2007-07-21 21:45:43 · answer #3 · answered by ♫●GARV●♫ 6 · 0⤊ 0⤋