can someone teach me to balance equation?

Question

I need to balance these equation but cant figure them out

1.CL2+NaBr> NaCL+Br2

2.Hgo+CL2> HgCL+O2

Answer 1

Basically, you have to have the same number of each element on both sides of the equation, so for #1, you have 2 Cl, 2 Na, and 2 Br on both the left and the right.

1 Cl2 + 2 NaBr > 2 NaCl + 1 Br2

For #2, you have 2 Hg, 2 O and 2 Cl on both sides.

2 HgO + 1 Cl2 > 2 HgCl + O2

Answer 2

Basically all you have to do is make sure the amounts on both sides of the equation are balanced. For example, on the first one you can see that bromine has 2. Look back at the other side of the equation. Write a two in front of the NaBr. Doing this now means that you have 2 sodium atoms on the left side and two atoms of bromine, but you don't have 2 atoms of sodium on the right side. Add a 2 in front of the NaCl. Now read your equation. You have 2 chlorine atoms on the left and 2 on the right. You have 2 atoms of sodium on the left and 2 on the right. You have 2 atoms of bromine on the left and on the right. Your equation is now balanced.

Answer 3

These can be balanced by inspection-
1. 2 Cl on the reactant side, so you must have 2 Cl on the product side-
Cl2 ---> 2 NaCl
Now you have 2 Na on the product side so you must have 2 Na on the reactant side-
2 NaBr ---> 2 NaCl
Now you have 2 Br on the reactant side so you must have 2 Br on the product side-
2NaBr ---> Br2
Putting this all together-
Cl2 + 2NaBr ---> 2 NaCl + Br2

You try the 2nd one.

Answer 4

1. Cl2 + 2NaBr ===>2NaCl + Br2

2. 2HgO + Cl2 ===> 2HgCl + O2

These are the easy ones. You just have to juggle them back and forth until every thing comes out. These are oxidation-reduction equations. Others are harder. Good luck.