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What's the amount of pure, 98%, liquid H2SO4 to be used in order to prepare a solution with a concentration of 0.02 N (normality)

2007-07-21 10:08:03 · 1 answers · asked by Jose 1 in Science & Mathematics Chemistry

1 answers

You do not specify the number of mL H2SO4 or the number of grams H2SO4. So I shall work it out both ways.Let the solution be called S.

Atomic weights: H=1 S=32 O=16 H2SO4=98

1LS x 0.02eqwtH2SO4/1LS x 1molH2SO4/2eqwtH2SO4 x 98gH2SO4/1molH2SO4 = 49g H2SO4

49gH2SO4 x 1mLH2SO4/1.84gH2SO4 = 27mL H2SO4

2007-07-21 10:22:20 · answer #1 · answered by steve_geo1 7 · 1 0

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