this was on my algebra 2 test. the choices where:
a.98 b.8 c.2/99 d.-2
i dont know if this is correct but i assume -2 is not one of the answers either.
2007-07-21 09:44:27 · 6 answers · asked by someone 2 in Science & Mathematics ➔ Mathematics
log(x+2) = log(x) + 2
Subtract log(x) from both sides
log(x+2) - log(x) = 2
Using Subtraction/Division rule
log((x+2)/x) = 2
Log definition
10^2 = (x+2) / x
100 = (x+2) / x
Multiply both sides by x:
100x = x+2
Subtract x from both sides :
99x = 2
Divide both sides by 99:
x = 2/99
so the answer is C
hope i helped you..
2007-07-21 10:05:53 · answer #1 · answered by Anonymous · 1⤊ 5⤋
Log(x+2)=logx+2 then Log(x+2)=logx+log100=log100x
then x+2 =100 x ,then x=2/99
2007-07-21 10:05:19 · answer #2 · answered by mramahmedmram 3 · 0⤊ 0⤋
log (x + 2) - log x = 2
log [(x + 2) / x ] = 2
(x + 2) / x = 10 ²
(x + 2) / x = 100
x + 2 = 100 x
2 = 99 x
x = 2 / 99
ANSWER c.
2007-07-21 10:03:07 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Log(x + 2) - Log(x) = 2
Log((x+2) / x) = 2
10^2 = (x + 2)/x
100x = x + 2
99x = 2
x = 2/99
C is the answer.
2007-07-21 09:51:10 · answer #4 · answered by Anonymous · 3⤊ 0⤋
log(x+2) = log(x) + 2
Subtract log(x) from both sides:
log(x+2) - log(x) = 2
Subtraction/Division rule for logs:
log((x+2)/x) = 2
Definition of log:
10^2 = (x+2) / x
100 = (x+2) / x
Multiply both sides by x:
100x = x+2
Subtract both sides by x:
99x = 2
Divide both sides by 99:
x = 2/99
2007-07-21 09:51:42 · answer #5 · answered by whitesox09 7 · 2⤊ 0⤋
log(x + 2) = log(x) + 2
subtract log x for both sides
log(x + 2) - log(x) = 2
quotient rule: log(a) - log(b) = log (a/b)
log{ (x + 2)/x } = 2
change to exponent rule
10^2 = (x+2)/x
100 = (x + 2)/x
100x = x + 2
99x = 2
x = 2/99
C
2007-07-21 09:58:01 · answer #6 · answered by 7 · 0⤊ 0⤋