Factor by grouping.
xy + 11x - 2y - 22
(x - 11)(y + 2)
(y - 11)(x + 2)
(x + 11)(y - 2)
(y + 11)(x - 2)
2007-07-21 08:51:27 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
lets do this by grouping common terms
xy+11x-2y-22=x(y+11)-2(y+11) notice that y+11 is common to both terms, so you get
(x-2)(y+11)
2007-07-21 08:54:31 · answer #1 · answered by careyschwartz 2 · 2⤊ 0⤋
xy + 11x - 2y - 22
Group them:
(xy + 11x) - (2y - 22)
Take out what is common then factor.
x(y + 11) - 2(y + 11) PS watch your signs here. :)
And now we see that (y+11) is common so keep that out, and put the other components together into one bracket.
(x - 2)(y + 11)
2007-07-21 15:55:51 · answer #2 · answered by Reese 4 · 1⤊ 0⤋
xy + 11x - 2y - 22 = 0
x(y + 11) - 2(y + 11) = 0
(x - 2)((y + 11) = 0
- - - - - - - -s-
2007-07-21 16:20:34 · answer #3 · answered by SAMUEL D 7 · 1⤊ 0⤋
(11x-22)+(xy-2y)
11(X-2)+y(x-2)
(X-2)(11+y)
2007-07-21 15:57:29 · answer #4 · answered by AZTECAMAN 4 · 0⤊ 0⤋