How much fence must be purchased in order to go around a field 9.84yds long & 16.69yds wide?

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How much fence must be purchased in order to go around a field 9.84yds long & 16.69yds wide?

2007-07-21 08:42:23 · 4 answers · asked by black cherry 1 in Science & Mathematics ➔ Mathematics

4 answers

Assuming that the yard is a rectangle and not "odd shaped" you would simply multiply the width by two, then multiply the length by two, then add them together:

Circumference = 2(L) + 2(W) = 2(9.84 yds.) + 2(16.69 yds.)

= 53.06 yds. of fence needed

2007-07-21 08:55:06 · answer #1 · answered by CellBioGuy 3 · 0⤊ 0⤋

Appx 50 yds. Dont forget to leave a opening.

2007-07-21 15:51:58 · answer #2 · answered by mike the dj 5 · 0⤊ 0⤋

9.84yds X 2

16.69yds X 2

Sum the results

2007-07-21 15:51:42 · answer #3 · answered by ed 7 · 0⤊ 0⤋

AMOUNT IS 2(LENGTH+WIDTH)=53.06YDS

2007-07-21 15:50:39 · answer #4 · answered by john 4 · 0⤊ 0⤋