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Use the quadratic formula to solve the equation.

9x^2-5x-3=0


Answer: The solution set is {_____,______}
(Simplify your answers. Type an integer or a decimal number with 4 decimal places, as needed, and in increasing order. Type N if there are no real solutions.)

2007-07-21 08:39:57 · 3 answers · asked by hllywdbabe7 1 in Science & Mathematics Mathematics

3 answers

Quadratic Formula

x = - b ± √b² - 4ac / 2a

9x² - 5x - 3 = 0

Let

a = 9

b = - 5

c = - 3

x = - ( - 5) ± √(- 5)² - 4(9)(- 3) / 2(9)

x = 5 ± √25 - 4(- 27) / 18

x = 5 ± √25 - ( - 108) / 18

x = 5 ± √ 25 + 108 / 18

x = 5 ± √133 / 18

x = 5 ± 11.53256259 / 18

- - - - - - - - -

Solving for +

x = 5 + 11.53256259 / 18

x = 16.53256259 / 18

x = 0.9184757

- - - - - - -

Solving for -

x = 5 - 11.53256259 / 18

x = - 6.532562596 / 18

x = 0.362920144

- - - - - - - -s-

2007-07-21 10:12:52 · answer #1 · answered by SAMUEL D 7 · 1 0

9x^2-5x-3=0

x = [-b +/- √(b^2 - 4ac)] / 2a

x = [5 +/- √((-5^2) - 4(9)(-3)] / 2(9)

x = [5 +/- √(25+108)] / 18

x = [5 +/- √(133)] / 18

2 answers:
x = [5 + √(133)] / 18 & x = [5 - √(133)] / 18
x = .9185 & x = -.3629

Increasing order: (-.3629, .9185)

2007-07-21 08:48:42 · answer #2 · answered by Reese 4 · 0 0

No real solution. So type N.

2007-07-21 08:54:40 · answer #3 · answered by Anonymous · 0 2

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