4x = 40
x = 10
20 + y = 18
y = - 2
2007-07-21 07:48:30
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answer #1
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answered by Como 7
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a million. in simple terms upload the two equations to a minimum of one yet another: 4x + 0y = 40 x = 10, and hence y = -2 2. Subtract the precise equation from the backside equation 3a - 0b = 12 a = 4, and hence b = 6 3. Substitution: n = 2m + 3 from first eq, and substituting into 2d: 3m = 2(2m + 3) - 9 3m = 4m - 3 m = 3, and hence n = 2*3 + 3 = 9
2016-12-14 15:30:55
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answer #2
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answered by ? 4
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2x + y = 18
+2x - y = 22
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(2x + 2x) + (y - y) = (18 + 22)
4x = 40
x = 10
Substitute x=10 into first equation:
2(10) + y = 18
y = 18 - 20
y = -2
Verify with 2nd equation:
2(10) - (-2) = 22
2007-07-21 07:47:15
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answer #3
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answered by Gorme 3
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2x + y = 18
2x - y = 22
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4x = 40
x = 10
2x + y = 18
2(10) + y = 18
y = 18 - 20
y = -2
(10,-2)
2007-07-21 07:43:58
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answer #4
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answered by fofo m 3
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4x=40
x=10
20+y=18
y=-2
2007-07-21 07:46:04
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answer #5
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answered by Anonymous
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add both equations and get
4x=40
x=10
2007-07-21 07:44:16
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answer #6
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answered by Kenneth H 3
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Good question. I'd like to piggyback and read the answers.
Is it ok, Y&A?
2007-07-21 07:52:24
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answer #7
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answered by Answernian 3
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