I'm reposting this question in order to continue discussion on this matter. See original posted question:
http://answers.yahoo.com/question/index;_ylt=AqDfOmto4wKkfjyBks2D4Prty6IX?qid=20070716085410AANyufm&show=7#profile-info-uDRfzKDFaa
2007-07-21
07:34:15
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2 answers
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asked by
Scythian1950
7
in
Science & Mathematics
➔ Mathematics
"Using a compass on a sphere" is the act of drawing a circle on the sphere, given a point on it, and a span. A span shall be defined to be that distance from the circle to the center, which is not the radius of the circle. In order to draw a great circle on the sphere, the correct span has to be found through construction. The problem is finding the exact span, given a sphere of unknown radius.
2007-07-21
08:25:31 ·
update #1
Practical difficulties of using a real compass on a ball shall be ignored.
2007-07-21
08:26:42 ·
update #2
Zanti, using a given compass span, a circle can be drawn, and its circumference divided into six parts, but only on a plane, not on a sphere. But anyway, the problem is to find the exact span, so that the great circle may be drawn for any given center. The problem is not to draw the great circle through a pair of points, that's a different problem.
2007-07-21
09:34:05 ·
update #3
If I pick two points on the sphere and draw two intersecting circles, I now have 4 points in a symmetrical diamond pattern. I can then immediately draw four more circles on the other side of the sphere. The centers of the 2 sets of four points would be antipodes of the sphere.
2007-07-21
09:36:22 ·
update #4
If the midpoint between 2 points can be found by compass construction on the sphere, then the method of drawing the great circle follows. It's already a tricky enough problem just to be able to do this on the plane, but I've left it open on whether or not this is even possible on the sphere.
2007-07-24
09:29:15 ·
update #5
Jeffrey, given 4 points in a diamond formation on a sphere, it's trivial to construct 4 more points in a diamond formation on the other side. They're not necessarily congruent, but they would have centers which are antipodes of the sphere.
2007-07-24
13:51:56 ·
update #6
I should add that this is a MATH problem, not a physical one using a real compass.
2007-07-24
16:06:46 ·
update #7