thats because the answers are 1,2 and 2,1
2007-07-21 06:42:01
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answer #1
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answered by tamumd 5
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There is no unique solution to this system of two equations
in two unknowns because both equations are equivalent...
y = -x + 3 is seen to be equivalent after you add X to both
sides to get to x + y = 3; hence the system becomes
x + y = 3 and
x + y = 3
This system has infinitely many solutions. (1,2) is one solution
but so is (2,1), (3,0), (0,3), (4, -1), (-1, 4)
If you were to graph these equations you would graph two
lines which are superimposed one on the other. Such lines
have infinitely many points in common.
2007-07-21 14:33:27
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answer #2
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answered by roger m 2
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(1,2) is one solution to the problem. However, there are many more sets of numbers that would work as well. A more generalized answer would be (x,3-x).
2007-07-21 13:47:11
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answer #3
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answered by Anonymous
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Since the two equations are the same, you have infinite number of solutions (x, -x+3), and (1,2) is just one solution.
2007-07-21 13:42:58
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answer #4
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answered by sahsjing 7
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You're not entirely wrong but your answer is incomplete. 1 and 2 can be used interchangeably with x and y. Let us demonstrate:
x = 1, y = 2
1st equation:
2 + 1 = 3
2nd equation:
1 = - 2 + 3
Assume: x = 1, y = 2
1st equation:
1 + 2 = 3
2nd equation:
2 = - 1 + 3
See? You're right only that the other aspect was not presented.
2007-07-21 14:00:54
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answer #5
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answered by Jun Agruda 7
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x=1, y=2 if x+y=3 then that would be 1=2=3 and y=-x+3, then it would be 2=-1+3 : that is the right answer!!!!
2007-07-21 13:49:42
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answer #6
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answered by hamradiotexas 2
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x + y = 3 and y = - x + 3 are one and the same thing----the equation of a straight lie of gradient(slope) = - 1. Line cuts y axis at (0 , 3) and x axis at (3 , 0).
Points that satisfy this are:-
(0 , 3) , (1, 2) , (2 , 1) , (3 , 0) etc
2007-07-25 04:22:51
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answer #7
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answered by Como 7
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x+y=3
y=x+3
put (3) in (1)
x+x+3=3
2x=0
x=0,y=3 OK. ANS.so the answer is (0,3) Not(1,2).
2007-07-21 13:52:27
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answer #8
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answered by Anonymous
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Both the equations are of same line.And since they overlap each other they'll have infinite set of solutions>>>>>>
2007-07-21 13:51:08
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answer #9
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answered by Rocky 1
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You have the same equation twice, which doesn't allow you to calculate values for the two unknowns.
You'd have to know the value of either x or y to solve the equation.
2007-07-21 13:48:06
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answer #10
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answered by Armafair 1
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