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How to factor 2t^2 - 9t - 7

show work please!!!

2007-07-21 04:47:45 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

since it doesn't factor out very nicely..

use the quadratic formula
(-b +/- √b^2 - 4ac) / 2a

quadratic formula is for things that look like
ax^2 + bx + c

so in your example:
a = 2
b = -9
c = -7

plug those values into the quadratic formula and solve. You'll come up with 2 answers between there's that + or -

2007-07-21 04:56:21 · answer #1 · answered by Julio 4 · 0 0

(2t + 1) (t - 7)

(t + 1) (2t - 7)

(2t - 1) (t + 7)

(t - 1) (2t + 7)

are the possible factors but none of them will give you the correct value for the t term. So, the equation has no factors. Use the quadratic equation's roots formula.

2007-07-21 04:57:28 · answer #2 · answered by Swamy 7 · 0 0

2t^2 - 9t - 7

Must use quadratic formula:
t = [-b +/- √(b^2 - 4ac)] / 2a

t = [9 +/- √(81 - 4(2)(-7))] / 2(2)

t = [9 +/- √(25)] / 4

t = [9 +/- 5] / 4

t = [9 + 5] / 4 and t = [9 - 5] / 4

t = 14/4 and t = 4/4
t = 7/2 and t = 1

2007-07-21 04:58:06 · answer #3 · answered by Reese 4 · 0 0

look for factors of 36: one million and 36 2 and 18 3 and 12 4 and 9 If the 36 is beneficial, the factors could desire to be an analogous sign (the two useful or damaging). If the 36 is damaging, the factors could desire to be opposite warning signs (one useful and one damaging). For the 1st problem, which of them upload as much as +9? +12 and -3 (undergo in innovations they could desire to be opposite warning signs) For the 2d problem, which of them upload as much as -13? -4 and -9 (the two an analogous sign) So, the solutions are: (t+12)(t-3) and (v-4)(v-9)

2016-10-09 04:50:20 · answer #4 · answered by ? 4 · 0 0

You don`t!
Could expression be:-
2t² - 9t + 7 which can be factorised:-
(2t - 7) (t - 1) ?

2007-07-21 21:26:43 · answer #5 · answered by Como 7 · 0 0

it has roots but they cannot be factored
all those who have given u are wrong answers do not follow with them
i have the solution eventhough with the same formula of
the above u will get
[9+or-(137)^0.5]/4


they are not resolvable there is no solution for the above equation.


for ur information use the following formula for having roots are not.
b^2-4*a*c=0or >0r <0

2007-07-21 05:32:17 · answer #6 · answered by koooooooooooool 2 · 0 0

reese did a good job at first but she lost a negative sign under the square root.
[9 +/- √(81 - 4(2)(-7))] / 2(2)

[9 +/- √(81 -(-56 ))] / 2(2)

[9 +/- √(137))] / (4)

always go back and check to make sure your answer works.

2007-07-21 06:05:58 · answer #7 · answered by jnice160 2 · 0 0

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