1. 3(x+3) > 2(x-1)
2. x+(2/3) < 5
3. (x-6)/5 > 5
4. (2x+3)/7 < 2
5. 3 < 2x +1 < 11
it's kindA HARD because of the <> signs,, by the way,, thanks,, :-)
2007-07-21 02:20:38 · 6 answers · asked by AriANe 1 in Science & Mathematics ➔ Mathematics
1. 3(x+3) > 2(x-1)
2007-07-21 02:24:50
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answer #1
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answered by sweet n simple 5
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3x+9 >2x-2
3x-2x> -2-9
x> -11
x<11
2. x+(2/3) < 5
x< 5-2/3
x<13/3
3. (x-6)/5 > 5
x-6> 25
x>31
4. (2x+3)/7 < 2
2x+3<14
2x<11
x<11/2
5. 3 < 2x +1 < 11
subtract 1
2<2x<10
divide by 2
1
Find for the values of x and compare the 2 equations:
1st: 3(x + 3) > 2(x - 1)
3x + 9 > 2x - 2
x = - 3 > x = 1
-9 + 9 > 2 - 2
0 > 0 is false; they are equal to each other
2nd: x + (2/3) < 5
x = - (2/3)
- (2/3) + (2/3) < 5
0 < 5 is true
3rd: (x - 6)/5 > 5
1/5x - 6/5
1/5x = 6/5
x = 6
6 - 6 > 5
0 > 5 is false
4th: (2x + 3) / 7 < 2
2/7x = -(3/7)
x = - (2/3)
- (2/3) + 3 = 2 1/3
2 1/3 < 2 is false
5th: 3 < 2x + 1 < 11 is false and true
2x - 1
x = - (1/2)
3 < - 1 < 11
3 < - 1 is false, - 1 < 11 is true
2007-07-21 04:58:25 · answer #2 · answered by Jun Agruda 7 · 2⤊ 0⤋
1. 3(x+3) > 2(x - 1)
3x + 9 > 2x - 2 // - 2x
x + 9 > -2 // - 9
x > -11
2. x + (2/3) < 5 // - (2/3)
x < 5-(2/3) = 4 + 1 - (2/3) = 4 + (1/3)
3. (x - 6)/5 > 5 // multiply by 5
x-6 > 25 // +6
x>31
4. (2x + 3)/7 < 2 // multiply by 7
2x + 3 < 14 // -3
2x < 11 // divide by 2
x < 5.5
5. 3 < 2x + 1 < 11 // -1
2 < 2x < 10 // divide by 2
1 < x < 5
2007-07-21 02:29:41 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
1. 3(x+3) > 2(x-1)
3x+9 > 2x-2
x+9 > -2
x > 7
2. x+(2/3) < 5
x < 4 1/3
3. (x-6)/5 > 5
x-6 > 25
x > 31
4. (2x+3)/7 < 2
2x+3 < 14
2x < 11
x < 5.5
5. 3 < 2x +1 < 11
2 < 2x < 10
1 < x < 5
2007-07-21 02:52:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1. 3(x+3) > 2(x-1) distribute
3x+9 > 2x-2 collect like terms (sub 2x from both sides, and sub 9 from both sides
= x > -11
2. x+(2/3) < 5 I like to clear out fractions. Mult each term by 3.
=3[x+(2/3) < 5]
=3x +2 < 15 sub 2 from both sides
= 3x < 13 divide both sides by 3
= x < 13/3
3. (x-6)/5 > 5 Clear out fraction. Mult both sides by 5
=5[(x-6)/5 > 5]
= x-6> 25 add 6 to both sides
x>31
4. (2x+3)/7 < 2 clear out fract by mult by 7
=7[ (2x+3)/7 < 2]
= 2x+3 < 14 sub 3 from both sides
= 2x< 11 divide both sides by 2
= x< 11/2
5. 3 < 2x +1 < 11 you can break this into two problems to simplify, or simplify as is. Let's break it into two this time.
3 < 2x +1 and 2x +1 < 11 see if you can solve this one !
2007-07-21 02:34:15 · answer #5 · answered by ktm 3 · 0⤊ 0⤋
The > < signs are just like = signs so it shouldn't be any harder.
I would help you out more but its too early on a SATURDAY morning for that crap lol.
2007-07-21 02:29:34 · answer #6 · answered by azrielle 3 · 0⤊ 0⤋