If you did the correct thing you will see that those 2 diagonal lines bisect each other at 90 degrees.
2007-07-21 01:14:40 · 8 answers · asked by tears 1 in Science & Mathematics ➔ Mathematics
8 triangles
2007-07-21 01:19:33 · answer #1 · answered by iyiogrenci 6 · 0⤊ 1⤋
If your square has corners ABCD, its diagonals will be the line segments AC and BD. Call the point where the diagonals meet E.
Now there should be 4 obvious right triangles whose right angle is at point E: ABE, BCE, CDE, and DAE.
There are also four right triangles formed with two of the square's sides and a diagonal: ABC, BCD, CDA, and DAB.
So there's 8 triangles formed.
2007-07-21 01:25:57 · answer #2 · answered by Tony The Dad 3 · 0⤊ 0⤋
8 triangles
2007-07-21 01:24:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I make it 4 small ones and 4 large ones
=8
2007-07-21 01:42:33 · answer #4 · answered by rosie recipe 7 · 0⤊ 1⤋
Eight is correct.
There's the obvious four...
Then when you add ajacent triangles (each forming 1/2 the square) you can make four other ones.
2007-07-21 01:26:09 · answer #5 · answered by George Y 7 · 0⤊ 1⤋
Eight triangles.
2007-07-21 01:23:10 · answer #6 · answered by Brahmanyan 5 · 0⤊ 1⤋
If you're working in 2 dimensions, the answer should be 4.
2007-07-21 01:18:49 · answer #7 · answered by Anonymous · 0⤊ 2⤋
eight
2007-07-21 01:20:34 · answer #8 · answered by just thinking 6 · 0⤊ 1⤋