2 consecutives odd integers have a sum of 48.What are the 2 odd integers?

Answer 1

let odd integers be 2x + 1 and 2x + 3
4x + 4 = 48
4x = 44
x = 11
Integers are 23 and 25

Answer 2

let x be the first odd integer = 23
let x + 2 be the 2nd odd integer = 25

x + x + 2 = 48 sum of 2 consecutive odd integers = 48
2x = 48 - 2
2x = 46
x = 23

x + 2 = 25

Answer 3

Consecutive unusual integers are 2 numbers aside: one million, 3, 5, 7, 9, 11, etc. For any unusual integer x, the subsequent unusual integer may be x+2, and the only after that must be x+4. that must be 3 consecutive unusual integers. three times the 2d integer may be 3(x+2). upload 14 to that, to get "14 extra effective than" it. hence, the respond is equation #2: x + (x+2) + (x+4) = 14 + 3(x+2)

Answer 4

Let the 2 odd integers be x and x+2.
x+x+2=48
2x+2=48
2x=46
x=23
.:the 2 no.s r 23 &25

Answer 5

first odd integer is (x-1)
second odd integer is (x+1)
(x-1)+(x+1)=48
so x =24
now odd integers are 23 , 25

Answer 6

Your two odd integers are 2n-1 and 2n+1.

(2n -1) + (2n + 1) = 48
4n = 48
n = 12
2n - 1 = 2(12) - 1 = 23
2n + 1 = 2(12) + 1 = 25

23 + 25 = 48

Answer 7

23 and 25.

Answer 8

lets suppose one of the integer to be x, the other must be y=x+2 add em and you got 48
x+y=48
x+(x+2)=48
2x+2=48
2x=46
x=23
This is one of the answer, the other is
y=x+2=23+2=25

The answers are 23 and 25.

Answer 9

23 + 25= 48

so its 23 and 25

Answer 10

let the twoconsecutive odd integers be 2n-1&2n+1;then
(2n-1)+(2n+1)=48
4n=48
n=12.
so the desired integers are23&25.ANS.