2007-07-21 00:13:04 · 9 answers · asked by ccaranay 1 in Science & Mathematics ➔ Mathematics
44 + 46 = 90
so its 44 and 46
2007-07-21 00:16:18 · answer #1 · answered by Holymasteric 3 · 1⤊ 1⤋
let x be the first even integer = 44
let x + 2 be the second even integer = 46
x + (x+2) = 90 sum of 2 consecutive even integers = 90
2x = 90 -2
2x = 88
x = 44
x + 2 = 46
2007-07-21 07:27:24 · answer #2 · answered by bluemaja_pooh 2 · 0⤊ 0⤋
Let x = smaller no., x + 2 = larger no.
Equation to solve x:
x + x + 2 = 90
2x = 90 - 2
2x = 88
x = 88 / 2
x = 44
Equation to solve x + 2:
44 + 2 = 46
Answer: smaller no. is 44, larger no. is 46, total is 90
2007-07-25 05:53:26 · answer #3 · answered by Jun Agruda 7 · 2⤊ 0⤋
44 and 46
(90/2 = 45)
45 -1 = 44
45 + 1 = 46
2007-07-21 07:17:05 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
Let integers be 2x and 2x + 2
4x + 2 = 90
4x = 88
x = 22
Answer is 44 and 46
2007-07-25 06:05:28 · answer #5 · answered by Como 7 · 0⤊ 0⤋
44&46
2007-07-21 07:28:28 · answer #6 · answered by janelle 2 · 0⤊ 0⤋
44 & 46
2007-07-21 07:22:02 · answer #7 · answered by texan_mailman 4 · 0⤊ 0⤋
Let the two consecutive even integers be 2n&2n+2;then
2n+(2n+2)=90
4n=88
n=22.
so the desired integers are 44&46.ANS.
2007-07-21 07:19:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋
x+ (x+2)= 90
2x+2= 90
x= 44
Numbers: 44 & 46
2007-07-21 07:17:58 · answer #9 · answered by Anonymous · 0⤊ 0⤋