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Let integers be 2x and 2x + 2
2x + 2x + 2 = 26
4x = 24
x = 6
Integers are 12 and 14

2007-07-24 22:34:43 · answer #1 · answered by Como 7 · 0 0

12 + 14 = 26

2007-07-21 00:14:35 · answer #2 · answered by Holymasteric 3 · 1 0

let x be the first even integer = 12
let x + 2 be the second even integer = 14

x + x + 2 = 26 sum of 2 consecutive even integers = 26
2x = 26 - 2
2x=24
x = 12

x + 2 = 14

2007-07-21 00:20:02 · answer #3 · answered by bluemaja_pooh 2 · 0 0

12 and 14

2007-07-21 00:15:01 · answer #4 · answered by stever002 3 · 0 0

there are 2 numbers x and y whose sum is 26 but y = x + 2
so x + y = x + x+ 2 = 26
2 x + 2 = 26
x = 12
y =14

2007-07-21 00:21:12 · answer #5 · answered by dr_no4458 4 · 0 0

let the two consecutive even integers be2n&2n+2;then
2n+(2n+2=26
4n=24
n=6.
so the desired integers are12&14. OK verifiedANS.

2007-07-21 00:26:41 · answer #6 · answered by Anonymous · 0 0

12 and 14

2007-07-21 00:14:33 · answer #7 · answered by Sammuelz_101 1 · 0 3

There are no two consecutive integers that I know of that come to 26.

12 and 14 are not cosecutive.

oh even. didn't see that part.

2007-07-21 00:15:51 · answer #8 · answered by Anonymous · 0 0

x+ (x+2)= 26
2x+2= 26
2x+24
x= 12
Numbers: 12 & 14

2007-07-21 00:15:32 · answer #9 · answered by Anonymous · 0 0

x + (x + 2) = 26
2x = 24
x = 12
x+ 2 = 14

2007-07-21 00:16:16 · answer #10 · answered by CPUcate 6 · 0 0

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