2007-07-20 22:44:54 · 7 answers · asked by mramahmedmram 3 in Science & Mathematics ➔ Mathematics
try to solve it usin vectors
2007-07-22 23:23:15 · update #1
Hint:
A+B+C=180
sinp+sinq=?
sin2A=2sinAcosA
2007-07-20 22:48:32 · answer #1 · answered by iyiogrenci 6 · 0⤊ 4⤋
it extremely is not genuine. attempt A = B = C = pi/3. Then the LHS is sin(2pi/3) = sqrt(3) /2 and the RHS is two*sin^2(pi/3)*cos(pi/3) = 2*(sqrt(3) /2)^2 *(a million/2) = 3/4. i finished up with sin(2A) - sin(2B) + sin(2C) = 4*cos(A)*sin(B)*cos(C), which does artwork with the above occasion records. i'm going to attend to take heed to from you relating to the accuracy of the given assertion till now spending the time writing out a evidence.
2016-11-10 01:14:02 · answer #2 · answered by weberg 4 · 0⤊ 0⤋
As A,B &C are angles of a triangle
A +B + C = pi
sin 2A + sin 2B + sin 2C
= 2 sinA cos A + 2 sin(B+C) cos(B-C)
= 2 sinA cos A + 2 sin(pi - A) cos(B-C)
= 2 sinA cos A + 2 sin Acos(B-C)
= 2 sinA(cos (pi - (B+C)) + cos(B-C))
=2 sin A(- cos(B+C) + cos(B-C))
=2 sin A(2sinB sin C)
= 4 sinA sinB sinC
2007-07-21 05:32:28 · answer #3 · answered by bharat m 3 · 3⤊ 0⤋
sin 2A + sin2B + sin2C
=2sinAcosA +2sin(B + C) cos(B − C)
=2sinA(−cos(B + C) + cos(B − C))
=4sinAsinBsinC.
2007-07-20 23:19:00 · answer #4 · answered by Anonymous · 2⤊ 0⤋
More details required
2016-07-29 09:58:48 · answer #5 · answered by ? 3 · 0⤊ 0⤋
ZUNAI??
no no, e 6 pure sano....
ke bono ke 6 nella foto...
2007-07-20 22:49:38 · answer #6 · answered by noodles 3 · 0⤊ 0⤋
you missed a letter or some brackets out? (its too early)
2007-07-20 22:49:59 · answer #7 · answered by Anonymous · 0⤊ 1⤋