Tara made x/y dollars, joe made x-y over y, lynn made 2/3 as much as tara, how much will they have all togethe

Answer 1

Tara x/y
joe (x-y)/y
Lynn = (2/3)(x/y)

(2x/3y)+ x/y + (x-y)/y = ?
multiply all by y
2x/3 + x + xy -y^2
multiply by 3
2x + 3x +3xy - 3y^2

Started it for you. Good luck

Answer 2

amount each made:

tara = x/y
joe = (x-y)/y
lynn = (2/3) (x/y) = 2x/3y

the total of theirs together will be,

= (x/y) + [(x-y)/y] + (2x/3y)

making the denominator same of each term by taking the LCM, we thus get,
LCM = 3y

= [(3x/3y)] + [(3x-3y)/3y] + [2x/3y]

now that the denominator is the same, we add up the numerators, thus we get,

= [3x + 3x - 3y + 2x] / 3y
= (8x - 3y) / 3y .... ANS

this is the total amount they will make together...


hope this helps!!! :-)

Answer 3

Whole= SUM(earnings)
Tara = x/y
Joe = (x-y)/y
Lynn = 2x/3y
Combining and finding LCD,
SUM = [3x + 3(x-y) + 2x]/3y = (8x-3y)/3y or
[8x/3y] -1

Answer 4

Tara --> x/y
Joe --> (x-y)/y
Lynn --> (2/3)x/y
T + J + L = x/y + (x-y)/y + (2/3)x/y
= (x+x - y + 2x/3)/y
= (2x+2x/3 - y)/y
= (6x/3 + 2x/3 - y)/y
= (8x/3 - y)/y

Answer 5

Tara has x/y dollars.
Joe has (x - y)/y dollars.
Iynn has 2[(x/y)/3] = (2x/3y) dollars.

Amount of money they had altogether
--> x/y + (x - y)/y + 2x/3y
= (x + x - y)/y + 2x/3y
= 3(2x - y)/3y + 2x/3y
= (6x - 3y + 2x)/3y
= (8x - 3y)/3y
= [(8x/3y) - 1] dolars

Answer 6

Total = x/y +(x-y)/y + (2x)/(3y)
= (3x + 3x-3y +2x)/3y
= $ (8x-3y)/3y

Answer 7

homework?