2 /10x -5 / 10/2x-1
2007-07-20 18:15:33 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Without brackets the question is meaningless----unfortunately.
2007-07-20 20:04:58 · answer #1 · answered by Como 7 · 0⤊ 0⤋
2 /10x -5 / 10/2x-1
(2 /10x -5) / (10/2x-1)
when dividing take the reciprocal of the second fraction and multiply, so you get
(2 /10x -5) * ((2x-1)/10)
and mulitply.(4x-2)/(100x-50)
the x's cancel out
2/50
1/25
that is if the brakets are how i assumed
2007-07-21 01:22:21 · answer #2 · answered by ebequeaith1792 1 · 0⤊ 0⤋
2/ 10x-5 / 10/ 2x-1
2/5(2x-1) /10/2x-1
2/ 5(2x-1) * 2x-1/10
1/5 * 1/5= 1/25
2007-07-21 02:08:03 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(2/10x-5) / (10/2x-1)
= (2/ 5(2x-1)) / ((2x-1)/10)
so, (2x-1) divide.
=2/5 *1/10
=1/25
2007-07-21 01:31:42 · answer #4 · answered by jj_fans 1 · 0⤊ 0⤋
(2/10x-5) / (10/2x-1)
= [2/5(2x-1)] / (10/2x-1)
= [2/5(2x-1)] * [(2x-1)/10]
= [2(2x-1)] / [50(2x-1)]
2x-1 gets cancelled from the (base) denominator and the numerator....
thus we get,
= 2/50
= 1/25 = 0.04 ..........ANS
hope this helps!!! :-)
2007-07-21 01:25:12 · answer #5 · answered by Sindhoor 2 · 0⤊ 0⤋
Please make your question clear by inserting brackets in your question.
2007-07-21 01:21:44 · answer #6 · answered by Anonymous · 0⤊ 1⤋