3m^2 + 15m over m^2 divide it by 30 over m^2 + 5m=?

Question

What is the denominator once its simplified

Answer 1

{ (3m² + 15m) / m² } / { 30 / (m² + 5m) }

{ (3 + 15/m) } / { 30 / (m² + 5m) }

{ (3 + 15/m) * (m² + 5m) } / 30

{ 3m² + 15m + 15m + 75 } / 30

{ 3 (m² + 10m + 25) } / 30

(m² + 10m + 25) / 10

(m + 5)² / 10

denominator is 10

Answer 2

[(3m^2 + 15m) / m^2 ] / [ 30 /(m^2 + 5m) ]

~~~~> [ 3(m^2 + 5m) * (m^2 + 5m) ] / 30 m^2

= [ (m^2 + 5m)^2 ]
--------------------
10 M^2

(M(m+5))^2 / 10 M^2 = [ M^2 (m+5)^2 ] / 10 M^2

So the denominator is 10 after cancelling M^2

Answer 3

10

Answer 4

Reading question as:-
[ (3 m ² + 15 m) / m² ] [(m ² + 5 m) / 30 ]
[ 3 m (m + 5) (m ² + 5 m) / 30 m ² ]
[ 3 m ² (m + 5) ² / 30 m ² ]
(1/10) (m + 5) ²
So denominator = 10

Answer 5

the answer comes out to 3m^4+15m^3 over 30m^2. the final answer is 3m^2+15m. when dividing fractions take the reciprocal of the second fraction and mulitiply

Answer 6

everywhere you spot an "m", positioned a -2 in it extremely is place. m2 + 5m + 9 whilst m = -2 (-2)2 + 5 (-2) + 9 A unfavorable situations a constructive is often unfavorable (-2)2 = -4 comparable with the subsequent area 5(-2) = -10 positioned the two negatives at the same time: -4 + -10 = -14 upload this answer to 9 -14 + 9 = 5 the respond is 5!

Answer 7

[(3m^2 + 15m) / m^2] * [(m^2 + 5m) / 30]

= [3(m^2 + 5m) / m^2] * [(m^2 + 5m) / 30]

thus after multiplying, we get,

= [3(m^2 + 5m)^2] / [30 m^2]

= [(m^2 + 5m)] / [10 m^2]

the denominator is 10 m^2


hope this helps!!! :-)

Answer 8

=(3m^2 +15m)(m^2 +5m) /(m^2 )(30)
=3m^4 +75m^2 +15m^3+15m^3 / 30m^2
=(3m^4/30m^2)+(75m^2/30m^2)+(30m^3/30m^2)
=1/10 m^2 +5/2 +m
=m^2+10m+25 =0
(m+5)(m+5) =0
m=-5

Answer 9

[3m^2 +15m]/[30/(m^2+5*m)] =
[3m^2 +15m]/30*(m^2+5*m)
m^2*[3*m+15]*[m+5]/30
m^2*[3*m^2+30*m+75]/30
[3*m^4+30*m^3+75*m^2]/30

That is what I get... 30? That seems too easy though, I would check my math.