4(0.18x+sqrt 2)=sqrt 11 x+1
x=_____
(round to nearest hundredth)
2007-07-20 17:42:29 · 5 answers · asked by hllywdbabe7 1 in Science & Mathematics ➔ Mathematics
2nd sqrt is only for 11, not the x+1 Thanks :)
2007-07-20 17:49:35 · update #1
2.58
2007-07-20 17:46:49 · answer #1 · answered by climberguy12 7 · 0⤊ 0⤋
Hi, I can't really tell you the answer, but I can show you how to solve it, and you can compute for it yourself.
4(0.18x + sqrt 2) = (sqrt 11)x + 1
0.72x + sqrt 2 = (sqrt 11)x + 1
(sqrt 2) - 1 = (sqrt 11)x - 0.72x
[(sqrt 2) -1] / [(sqrt 11) - 0.72] = x
So just compute for x then.
Hope that helps!!!
2007-07-21 00:53:35 · answer #2 · answered by Moja1981 5 · 0⤊ 0⤋
Tell me that you at least know WHAT to do? Brackets mean you must multiply the number outside the bracket into the brackets. Multiply 4 X 0.18 and 4 X root 2.
Then collect all the "x"'s on one side of the equal sign, and the numbers on the other and solve for x.
Not that tough a question, really.
2007-07-21 00:54:03 · answer #3 · answered by huckleberry 5 · 0⤊ 0⤋
is the 2nd sqrt for 11,11x or 11x+1?
2007-07-21 00:48:33 · answer #4 · answered by 037 G 6 · 0⤊ 0⤋
let me ask my brother in law.. he goes to MIT
2007-07-21 00:45:55 · answer #5 · answered by ijustdid_23 1 · 0⤊ 0⤋