Help with factoring:?

Question

Solve the following by factoring:

a) x^2+6x-16=0


b) 6x^2+42x=0

Answer 1

a) should be easy since you don't have any real difficult numbers to work with, otherwise you'll need the quadratic equation.
- c=-16....so think about what factors multiplied together equal 16 (1 and 16, 2 and 8, 4 and 4)
- b= 6.....so using those factors above what two combinations can equal 6? 8-2=6

(x-2)(x+8) --> x = 2 and x = 8

b) to make it as easy as possible...divide the equation by 6
x^2 + 7x=0
x^2 = -7x ....divide both sides by x
x = -7

Answer 2

a)x^2+6x-16=0
look for two numbers that multiply to 16 with a difference of 6. You get 8 and 2. These go in the brackets.

x^2+6x-16=0
(x-2)(x+8)=0
so, x=2 or x=-8


b) 6x^2+42x=0
Take out a common factor of 6x

6x(x+7) =0
so, x=0 or x=-7

Answer 3

a) x^2+6x-16=0
(x+8)(x-2)=0
x+8=0 and/or x-2=0
x+8-8=0-8 x-2+2=0+2
x=-8 x=2

b)6x^2+42x=0
x(6x+42)=0
x=0 and/or 6x+42=0
x=0 6x+42-42=0-42
6x=-42
6x/6=-42/6
x=-7

hope this does it for you

Answer 4

a)
x^2 + 6x - 16 = 0
Factoring:
(x + 8) (x - 2) = 0
Answer:
x is either - 8 or 2.

b)
6x^2 + 42x = 0
Factoring:
6x (x + 7) = 0
Answer:
x is either 0 or + 7.

Answer 5

a) (x+8)(x-2)=0
x+8=0 => x=-8
x-2=0 => x=2

b) x(6x+42)=0
x=0
6x+42=0
6x=-42
x=-7

Answer 6

a. (x+8)(x-2)
b. 6x(x+7)

Answer 7

a) (x + 8) (x - 2) = 0
x = - 8 , x = 2

b) 6x (x + 7) = 0
x = 0 , x = - 7

Answer 8

(x-2)(x+8)

(6x)(x+7)

Answer 9

Where:
ax^2+bx+c=0

x= -b +/- (the square root of) {b^2 - 4ac} all divided by 2a