Line L goes through B(3,4,-2) and C(7,-1,5).
Calculate the directional vector v and its magnitude.
v = BC = = <7-3, -1-4, 5+2> = <4, -5, 7>
| v | = √(4² + (-5)² + 7²) = √(16 + 25 + 49) = √90
Write the equation of the line.
L = B + tv
L = <3, 4, -2> + t<4, -5, 7>
Calculate the vector AB.
Let
u = AB = = <3-2, 4+6, -2-1> = <1, 10, -3>
Take the cross product.
AB X BC = u X v = <1, 10, -3> X <4, -5, 7> = <55, -19, -45>
| u X v | = √[55² + (-19)² + (-45)²] = √5411
Calculate the distance h, of A from the line L.
h = | u X v | / | v | = √5411 / √90 = √(5411/90) ≈ 7.7538521
2007-07-20 15:10:58
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answer #1
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answered by Northstar 7
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