Can someone explain the logic behind this problem? How do I solve it, and how did you figure it out?
Mike said that when he opened his book, the product of the page numbers of the two facing pages was 7007. Without performing any calculations, prove that he was wrong.
2007-07-20 13:24:44 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Facing page numbers are one odd and one even number, and odd X even is always even.
2007-07-20 13:28:05 · answer #1 · answered by hayharbr 7 · 8⤊ 0⤋
Without performing any calculations...umm-m...
Facing pages must be odd and even number pages.
the product of any odd and even number is always even.
7007 is not an even number, so that cannot be correct.
Mike is wrong.
Unless he was at the back of the book, and the last page was 7007 and the next page was blank. In my mind that is cheating because you said the product of the "page numbers", and a blank page doesn't count. As in , 7007 times nothing is nothing.
2007-07-20 14:05:26 · answer #2 · answered by zahbudar 6 · 0⤊ 0⤋
The two facing pages will always be two consecutive numbers-ie. one even number and one odd number. While multiplying numbers if any one of the numbers is an even number the product will be an even number. In this problem 7007 is not an even number. So in the page numbers there was not an even number. Hence the statement of Mike is wrong.
2007-07-20 13:41:35 · answer #3 · answered by Joymash 6 · 0⤊ 0⤋
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2016-12-10 17:51:29 · answer #4 · answered by matheis 4 · 0⤊ 0⤋
its true it is incorrect coz no two sequentic numbers(eg.23 and 24) can give the product of 7007. it ranges from 84*85 to 84*83.
2007-07-20 13:36:24 · answer #5 · answered by **PiNoY YFC** 7 · 0⤊ 0⤋
Answer number one. Odd/even products are always even.
2007-07-20 13:34:09 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the product of an odd and an even number will always be even.
2007-07-20 13:33:45 · answer #7 · answered by Anonymous · 0⤊ 0⤋
no two consecutive numbers is equal to 7007
2007-07-20 13:32:08 · answer #8 · answered by forgetfulpcspice 3 · 0⤊ 2⤋
there are no simultaneous factors of 7007
and book numbers are usually simultaneous (1 and 2, 3 and 4 etc)
2007-07-20 13:30:48 · answer #9 · answered by Anonymous · 0⤊ 2⤋