A = 1/2 (base1 + base2)(height)
A = 1/2 (6 + 15)(12)
A = (21)(6)
A = 126 sq. feet
2007-07-20 09:54:33
·
answer #1
·
answered by Don E Knows 6
·
0⤊
0⤋
Use formula: area of trapezoid.
A = ( h/2 )(a + b)
A = (12/2) (6 + 15)
A = (6) (21)
A = 126 ft.^2
PS You could also do this by finding the area of rectangle and 2 area of triangles and adding them together.
A = 1/2 bh
A = 1/2 (4.5)(12)----------------> You can find base from subtracting the opposite side of the rectangle and dividing by 2. (15-6 = 9/2 = 4.5)
A = 27 (and you have 2 triangles.... so that's 54 ft. ^2 total)
A = lw
A = (6)(12)
A = 72 ft^2
Total of the 3 parts: 72 ft^2 + 54 ft^2 = 126 ft.^2
2007-07-20 09:56:26
·
answer #2
·
answered by Reese 4
·
0⤊
0⤋
Area = (1/2) (12) (6 + 15) ft ²
Area = 6 x 21 ft ²
Area = 126 ft ²
2007-07-21 12:12:39
·
answer #3
·
answered by Como 7
·
0⤊
0⤋
(6+15 )x12/2 = 126 square feet
2007-07-20 09:53:53
·
answer #4
·
answered by mramahmedmram 3
·
0⤊
0⤋
Memorize those formulation or they are going to come back and chew you in each and every math classification you're taking!!! area of Parallelogram (A) is comparable to the backside(b) cases the peak(h): A=bh area of a trapezoid(A) is comparable to one-0.5 (a million/2)cases the sum of the bases(b?+ b?) cases height(h) A= a million/2(b?+ b?)*h Circumference(C) of a circle is comparable to "pi"(?) cases the diameter(d); C= ?*d area(A) of a circle is comparable to "pi" (?) cases the radius(r) squared: A = ? r² Perimeter(P) of a rectangle is the sum of two lengths(L) and a pair of widths(W): P = 2L + 2W area(a) of a triangle is equivalent tyo one-0.5(a million/2) cases the backside(b) cases the peak(h): A= a million/2bh in simple terms stick to those formulation.
2016-12-14 14:39:43
·
answer #5
·
answered by ? 4
·
0⤊
0⤋
126ft^2
2007-07-20 09:55:35
·
answer #6
·
answered by Matt T 1
·
0⤊
0⤋