What is the slope of a line PERPENDICULAR to the line passing through the given points P (6,-1), and Q (3,-2).?? Do I use the regualr formula? I am not sure? Does anybody know of any websites I can get some help from???
2007-07-20 07:15:40 · 7 answers · asked by 777 6 in Science & Mathematics ➔ Mathematics
(-2-(-1))/(3-6)= 1/3, so take the negative reciprocal to get the perpindicular slope: -3
2007-07-20 07:20:25 · answer #1 · answered by adambauman31 2 · 3⤊ 0⤋
The line through the given points has slope m=(-1+2)/(6-3)=
1/3 so the ,perpendicular has slope m´=-3
2007-07-20 14:22:01 · answer #2 · answered by santmann2002 7 · 2⤊ 0⤋
The product of slopes of the line and slope of the perpendicular is -1.
so slope of line PQ= -2+1 / 3-6
m= -1/-3 =1/3
so slope of line perpendicular to this line is -3
(1/3 x m2 = -1 so m2 = -3)
2007-07-20 14:17:37 · answer #3 · answered by sweet n simple 5 · 2⤊ 0⤋
First get the slope of the given data points:
m - Slope.
m1 = (y2 - y1)/ (x2 - x1)
m1 = (-1 - (-2))/ (6 - 3)
m1 = (-1 + 2)/ (6 - 3)
m1 = 1/ 3
With Perpendicular lines, the values of the slopes multiplied together give -1.
m1*m2 = -1
1/3 *m2 = -1
m2 = -1/ (1/3)
m2 = -3
2007-07-20 14:27:55 · answer #4 · answered by Sparks 6 · 2⤊ 0⤋
= -3
2007-07-20 14:19:44 · answer #5 · answered by Etymologist 3 · 1⤊ 1⤋
Use the regular formula.
2007-07-20 14:23:23 · answer #6 · answered by Susan S 7 · 2⤊ 1⤋
http://www.purplemath.com/modules/index.htm
its great for math help i used it all through High School
2007-07-20 14:21:06 · answer #7 · answered by casey_1314 1 · 2⤊ 1⤋