What is the distance from the point (-1,-3) to the line y=2?

Answer 1

This one is pretty simple because y = 2 is a horizontal line. The y value never changes. The point on y=2 that is closest to (-1,3) will be (-1,2). The y value has to be 2, and the x value is just the x value of the given point.
Just take the absolute value of the difference in the y values.
| -3 -2 |
= | -5 |
= 5
The shortest distance is 5.

Answer 2

From the point x=-1, y=-3 to the line y=2 the distance would be 5, it would be 3 unites below zero +2.units after zero.

Answer 3

5

Answer 4

5

Answer 5

The distance is basically the prependicular drawn from the point (-1,-3) to the line y=2

so whatever the value of x in the point it does not effect its distance from the line y=2

the distance is |(-3-2)/a|
(here a is the coefficent of y ie 1 in this case)

so the ans. is 5.

Answer 6

y = 2 is a horizontal line passing thro` (- 1 , 2)
Distance, d , from (- 1 , - 3) to (- 1 , 2) is the vertical distance between these two points.
d = 5

Answer 7

There are an infinite number of distinct distances from that point to that line. Do you mean to say the shortest distance?

Answer 8

5, the absolute difference between 2 and -3

Answer 9

Pythagoras would claim sqrt( (x - x1)^2 + (y - y1)^2) where x1 = -1 and y1 = -3, y=2, x = x

Answer 10

1

x =0 so the distance is just the x ordinate.