Can someone help me solve this prob?

Question

(x^2+5x+4)/(x+3)^2 Divided by (x+1)/(x^2-9) Thank You

This is not my homework, I am just trying to brush up on my math before school starts.

Answer 1

(1) Factor it out:

[ (x+4)(x+1)/(x+3)^2 ] / [ (x+1) / (x+3)(x-3) ]

(2) Divide by multiplying by the reciprocal:

[ (x+4)(x+1)/(x+3)^2 ] / [ (x+1) / (x+3)(x-3) ] =
[ (x+4)(x+1)/(x+3)^2 ] * [ (x+3)(x-3) / (x+1) ] =
(x + 4)(x + 1)(x + 3)(x - 3) / [ (x + 3)(x + 3)(x + 1) ]

(3) Cancel identical terms (x+1) and (x+3) from both the numerator and denominator:

(x + 4)(x + 1)(x + 3)(x - 3) / [ (x + 3)(x + 3)(x + 1) ] =
(x + 4)(x - 3) / (x + 3)

That's your answer. You can multiply out the two terms if you want:

(x + 4)(x - 3) / (x + 3) =
(x^2 + x - 12) / (x + 3)

Answer 2

mmm its instersitng ...we are doing your homework lol

(x^2 + 5x + 4)(x^2-9) / ( (x + 3)^2 (x+1) )

(x^2 + 5x + 4)(x+3)(x-3) / (( x+3)^2 (x+1) )

(x+4)(x+1)(x-3) / (( x+3) (x+1) )

(x+4)(x-3) / ( x+3)

Answer 3

X^2+5x+4 = (x+1)(x+4)
Therefore, problem reduces to

(x+1)(x+4)/(x+3)(x+3)
----------------------------
(x+1)/(x+3)(x-3)

= (x-3)/(x+3)