A Solution used to chlorinate a pool contians 7% chl. by mass. An ideal chl. level is one part per million.?

Question

(think of of 1ppm as 1 g of chl. per 1 million grams of water) The density for water is 1.00 g/ml and the density of chl. is 1.10 g/ml. What volume of the chl. is requiered to produce a chl. level of 1 ppm in an 18,000 gallon pool?

Answer 1

9.734 Liters of the solution to get 1ppm in the pool.

Answer 2

Here is the 2 step plan:


1. find mass of water, need to convert 18000 gal to c^3
by using
1 Gallons (US) = 3785.41178 Cubic Centimeter

so we have 68137412.04 cc of water and at 1gm/cc this is also grams of water in the pool. for 1ppm of chlorine you will need 68.137gm of chlorine in that pool.

2 . to find the volume of the chlorine 68.137 / 1.1=61.943 mL of pure chlorine is needed to get 1ppm in the pool.

Now I think the question is asking how much of the 7% is needed to attain the 1ppm in the pool.if that is the case then:

7% by mass = 7 gm Cl / Liter water so to get 68.137 you need 68.137 / 7 = 9.734 Liters of the solution to get 1ppm in the pool.

Answer 3

18000*3785/1000000*.07*1.1= 885 ml of solution