Let's put that in equation form first, shall we.
A = J +3
(i.e. Anna is 3 years older than Jody)
A+5 + J+5 = 24
(i.e. five years from now, the sum of their age will be 24)
Which can be rearranged to be A+J=14
Since A = J+3, we can replace the A in the other equation, getting
(J+3)+J=14
2J=11
or J=5 1/2
Jody is 5 1/2, Anna is 8 1/2 (3 years difference)
Five year from now, Jody will be 10 1/2 and Anna 13 1/2; and the total of their age will be 24.
2007-07-20 00:26:20
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answer #1
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answered by Vincent G 7
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Let x = Jody's Age
Let x + 3 = Anna's Age
x+ x + 3 = 24 - 5
2x = 19 - 3
x = 16/2
x = 8 years
Jody's Age = 8 years
Anna's Age = 11 years
To check:
8 + 8 + 3 = 24-5
19 = 19
2007-07-20 07:31:11
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answer #2
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answered by Juan Pedro 2
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Let jody's age now be x
thus in 5 years she'll be X + 5
If Anna is 3 yrs older,her age then wud be 3 + (X+5)
eqn; X+5+3+(X+5)=24
2X+13=24
2X=11
X=5.5 ~ 6yrs
Jody is 6 and Anna is 9
2007-07-20 07:51:01
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answer #3
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answered by tbaz4us 2
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age of Jody = j age of anna j+3
in five years jody's age j+5
and anna's age j+8
the sum j+5+j+8 = 24
2j+13 = 24
2j=11
j=5.5y and for anna anna's age a=8.5y
2007-07-20 07:22:35
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answer #4
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answered by maussy 7
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let a be the age of Anna and j be the age of Jody
a = j + 3
a + 5 + j + 5 = 24
a + j + 10 = 24
a + j = 14
j + 3 + j = 14
2j = 11
j = 5.5
a = 5.5 + 3 = 8.5
2007-07-20 07:26:28
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answer #5
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answered by 7
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let anna x
jody y
x-y=3
x+5+y+5=24
x+y+10=24
x+y=24-10
x+y=14
x-y=3
------------------add
2x=17
x=17/2
y=14-17/2=11/2
2007-07-20 07:43:09
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answer #6
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answered by Anonymous
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not possible unless you use half years
2007-07-20 07:40:35
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answer #7
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answered by Kilty 5
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Is this even possible?
2007-07-20 07:20:42
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answer #8
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answered by Anonymous
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