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Find the exact value of the inverse trig function.

sin(cos^-1 (1/2))

2007-07-19 23:28:56 · 5 answers · asked by journey 1 in Science & Mathematics Mathematics

5 answers

sin(cos^-1 (1/2))
=?

let x=cos^-1 (1/2)
1/2=cosx
x=60

sin60=sqrt(3)/2

2007-07-19 23:41:21 · answer #1 · answered by iyiogrenci 6 · 0 0

NO! the arc's or specifically sin^-1, cos^-1, tan^-1 are functions used to find angles. This is why they are sometimes called arcsin, arccos, arctan, to avoid confusion with 'inverses'. In the case of trig fucntions, cosec, sec, and cot can be seen as reciprocals rather than inverses. Inputting the reciprocals into a calculator is simple. Eg. for sec(x) simply put in cos(x), but put a 1 over it. should look like this: Y=1/(cos(x)) graphing gives the graph of Y=sec(x) Get it?

2016-05-18 01:29:38 · answer #2 · answered by thersa 3 · 0 0

cos x = 1/2

since cos = adj / hyp

we know that
adj = 1
hyp = 2

using pythagorean theorem, we find
opp = sqrt 3

sin x = opp / hyp = (sqrt 3) / 2

2007-07-20 03:06:30 · answer #3 · answered by Mathematica 7 · 0 0

cos^-1(1/2) = 60

sin(60) = sqrt(3)/2

so the answer is sqrt(3)/2

2007-07-19 23:39:51 · answer #4 · answered by      7 · 0 0

♠ y=sin(acos(1/2)); 1/2=cos60°; y=sin60 =0.5*sqrt(3);

2007-07-19 23:39:21 · answer #5 · answered by Anonymous · 0 0

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