A person has 99 cows and 9 sons. Each cow has been given a number from 1 to 99 and each cow gives milk equal to its number. How will we divide cows between 9 sons so that each son gets equal amount of milk.
2007-07-19 21:30:24 · 13 answers · asked by C00L GαL 2 in Science & Mathematics ➔ Mathematics
Let us break it down.
First, find the arithmetic total of the number of cows.
Sum= 99/2 * (1+99)
=4950
This number must be divided evenly between the sons as per your question.
4950/9 = 550
Now, there are multiple ways to do this. One way is to just give each son a cow plus another cow until the numbers add up to 550. Then, repeat the procedure with each son. However, if you want each son to receive equal amount of milk and an equal number of cows the solution is unique. Each son will need 11 cows. The average of each cow must then be 50.
Here is one solution: 1, 18, 19, 36, 37, 54,55, 72, 73, 90,95
2007-07-19 21:51:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
its vry easy ...heres the ans....jus have a look...its vry easy to understand...
1 2 3 4 5 6 7 8 9
18 10 11 12 13 14 15 16 17
26 27 19 20 21 22 23 24 25
34 35 36 28 29 30 31 32 33
42 43 44 45 37 38 39 40 41
50 51 52 53 54 46 47 48 49
58 59 60 61 62 63 55 56 57
66 67 68 69 70 71 72 64 65
74 75 76 77 78 79 80 81 73
82 83 84 85 86 87 88 89 90
99 98 97 96 95 94 93 92 91
all the cloumns all add to 550!!
2007-07-19 22:04:00 · answer #2 · answered by Rajat Gupta 2 · 4⤊ 0⤋
1st son -99 ,10 ,90 ,19 ,81 ,28 ,72 ,37 ,63 ,51 =550
2ndson-98 ,11 ,89 ,20 ,80 ,29 ,71 , 38 ,62 ,52 =550
3edson-97 ,12 ,88 ,21 ,79 ,30 ,70 ,39 , 61 ,53 =550
4thson- 96 ,13 ,87 ,22 ,78 ,31 ,69 , 40 ,60 ,54 =550
5thson- 05 ,95 ,14, 86, 23, 77, 32, 68, 41, 59,50 =550
6thson- 01, 06, 94, 15, 85, 24, 76, 33, 67, 42, 58, 49 =550
7thson-02, 07, 93, 16, 84, 25, 75, 34, 66, 43, 57, 48 =550
8thson-03, 08,, 92, 17, 83, 26, 74, 35, 65, 44, 56, 47 =550
9thson-04, 09, `91, 18, 82, 27, 73, 36, 64, 45, 55, 46 =550
2007-07-20 04:33:21 · answer #3 · answered by Amidhala S 2 · 1⤊ 0⤋
the total number of [gallons of?] milk from all 99 cows would be
1+2+3+4+...+99 = 99x100/2
so each son would get [99x100/2]/9 = 11x50=550 milk gallons.
what you could do now would be to divide the cows such that each son would get 550 milk gallons from his cows.
2007-07-19 21:38:10 · answer #4 · answered by jman 2 · 2⤊ 0⤋
99/ 9 = 11
2007-07-25 06:04:17 · answer #5 · answered by tony10 1 · 0⤊ 0⤋
SIMPLE!!
Shoot the cows then every one gets the an equal amount of milk. NONE!
Naw j/k I just don't feel like doing the work since I'm sick. But it is simple.
2007-07-19 22:03:22 · answer #6 · answered by Crizzy 2 · 1⤊ 0⤋
11 i think if you divide you will get 11
2007-07-19 21:39:41 · answer #7 · answered by Anonymous · 0⤊ 0⤋
each get a gallon of milk a day
2007-07-19 21:33:30 · answer #8 · answered by Anonymous · 0⤊ 3⤋
Are you satisfied with above answers ?
2007-07-25 01:21:16 · answer #9 · answered by Pranil 7 · 0⤊ 0⤋
ah! i guess-author of your book is Verghese Kurien
2007-07-20 01:22:15 · answer #10 · answered by Posiedon 3 · 1⤊ 0⤋