What is the derivative of 4th Root X^3?

Answer 1

d/dx (x^n) = n(x^(n-1)) , where n is the exponent.

x^3/4

d/dx (x^3/4) = 3/4 (x^(3/4 - 1)
derivative = 3/4 (x^(-1//4))
derivative = 3/(4x^1/4)

Answer 2

The fourth root of x^3 is x^(3/4).
The derivative is:
(3/4)x^(3/4 - 1)
= (3/4)x^(-1/4)
= 3 / [ 4 * (4th root of x) ].

Answer 3

4th root x^3 = x^3/4
derivative =3/4x^-1/4 = 3/(4x^1/4)

Answer 4

f (x) = x^(3/4)
f `(x) = (3/4) x ^(-1/4)
f `(x) = 3 / [ 4 x^(1/4) ]

Answer 5

for a 2d diploma equation to have not got any actual roots, its graph does no longer bypass the x axis. this takes place collectively as the discriminant is undefined. the discriminant would have been sq. root of [ok^2 - 4(a million)ok] it extremely is the sq. root of a unfavourable extensive form for this reason ok^2 - 4k < 0 and so ok(ok - 4) < 0 meaning that ok>0 collectively as ok - 4 < 0 or the era 0 < ok < 4 OR ok<0 collectively as ok - 4 >0 which has no answer So the respond is ]0,4[ or utilising diverse notation 0 < ok < 4

Answer 6

y = (x^3)^(1/4)

y = x^(3/4)

y' = 3/4 x^(3/4 - 1) d/dx (x)

y' = 3/4 * 1/x^(1/4)

y' = 3 / (4x^(1/4) )

Answer 7

d/dx(x^3) = 3x^2