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for algebra one, i suck at math... heres what im talking about (x-y)(6x+4y)
anyone?

2007-07-19 09:29:43 · 7 answers · asked by jess 1 in Science & Mathematics Mathematics

7 answers

Use FOIL.It stands for the sum of the products of the:
* [F]irst terms (x * 6x) of each sum
* [O]uter terms (x * 4y) furthest apart
* [I]nner terms (-y * 6x) closest together
* [L]ast terms (-y * 4y) of each sum

Adding that up, its:

6x^2 + 4xy - 6xy - 4y^2

Combining like terms:

6x^2 - 2xy - 4y^2

2007-07-19 09:33:57 · answer #1 · answered by McFate 7 · 0 0

Multiply the terms one at a time: multiply the first term in the first expression by each term in the second expression, and then multiply the last term in the first expression by each term in the second expression:

(x-y)(6x+4y) = x(6x+4y) - y(6x+4y) = 6x^2 + 4xy - 6xy + 4y^2 = 6x^2 - 2xy + 4y^2

2007-07-19 16:36:49 · answer #2 · answered by dansinger61 6 · 0 0

First take x(6x+4y) getting 6x^2 +4xy
Then take -y(6x+4y) getting -6xy -4y^2
Now add the results getting 6x^2 -2xy -4y^2

2007-07-19 16:39:39 · answer #3 · answered by ironduke8159 7 · 0 0

Multiply x with (6x + 4y):
6x^2 + 4xy

Multiply -y with (6x + 4y):
-6xy - 4y^2

Add them:
6x^2 - 2xy - 4y^2

2007-07-19 16:36:22 · answer #4 · answered by gebobs 6 · 0 0

You use FOIL. FOIL stands for FIRST, OUTSIDE, INSIDE, LAST.

F = FIRST ---- you multiply the first term in the first set of parentheses with the first term in the second set of parentheses: (# + _)(# + _)

x * 6x = 6x^2


O = OUTSIDE ------ you multiply the outside terms, which means you multiply the first term in the first set of parentheses with the second term in the second set of parentheses:
(# + _)(_ + #)

x * 4y = 4xy


I = INSIDE ------ you multiply the inside terms, which means you multiply the second term in the first set of parentheses with the first term in the second set of parenthese:
(_ + #)(# + _)

-y * 6x = -6xy


L = LAST ------ you multiply the last terms, which means you multiply the last term in the first set of parentheses with the last term in the second set of parentheses: (_ + #)(_ + #)

-y * 4y = -4y^2


Now, you add all of these together:

6x^2 + 4xy - 6xy - 4y^2

Now you have two like terms (4xy and -6xy) so you can combine them:

6x^2 - 2xy - 4y^2

2007-07-19 16:43:11 · answer #5 · answered by nona 3 · 0 0

(x - y)(6x + 4y)
Use the FOIL Method (First Outer Inner Last)

First: x(6x) = 6x^2
Outer: x(4y) = 4xy
Inner: -y(6x) = -6xy
Last: -y(4y) = -4y^2

Add them all up:
6x^2 + 4xy - 6xy - 4y^2

Group like terms:
6x^2 - 2xy - 4y^2

6x^2 - 2xy - 4y^2 is your answer

2007-07-19 16:40:05 · answer #6 · answered by kousuke51 2 · 0 0

(6x + 4y) * x = 6x^2 + 4xy
(6x + 4y) * (-y) = - 6xy - 4y^2

6x^2 + 4xy - 6xy - 4y^2

6x^2 - 2xy - 4y^2 is the answer

2007-07-23 05:25:29 · answer #7 · answered by Jun Agruda 7 · 2 0

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