a club with 20 women and 17 men needs to form a committee of size six. How many committees are possible if the committee must have three women and three men?
2007-07-19 09:08:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
you use nCr
n! / (n-r)! r!
so, (20C3+17C3) / 37C6
2007-07-19 09:12:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Is that the whole question? Because then it has to be 5. That would be 15 women and 15 men.....5 women and 2 men would be left, which couldn't make another group because there would not be 3 men left. I'm thinking that that is not the entire question though. Does it say atleast or atmost anywhere in the question? Or is there any words that were left out?
2007-07-19 16:20:57 · answer #2 · answered by Ruby 1 · 0⤊ 1⤋
(20*19*18/2*3)*(17*16*15/2*3) = 62791200
Yes, more than 62 millions.
2007-07-19 16:12:56 · answer #3 · answered by oregfiu 7 · 0⤊ 0⤋