-4x^2 - 19x + 63
= (x + 7)(-4x + 9)
2007-07-19 09:10:01
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answer #1
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answered by Mathematica 7
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Here is a step by step:
1) Multiply -4 (from -4x^2) by 63: -4 x 63 = -252
2) What factors of -252 add up to -19 (from 19x)
-28 x 9 = -252, -28 + 9 = -19
3) Write problem by breaking up -19x, lining them up by factors of first variable (4 is a factor of 28) and last constant
(9 is a factor of 63), (-4x^2 +9x -28x +63 will not work.)
-4x^2 -28x + 9x + 63
4) Factor front two numbers and last two numbers:
-4x(x+7) + 9 (x+7)
Note that you will always the same term in ( ).
5) Redistribute: (-4x+9)(x+7)
That is your answer.
This method will work for most problems with an x^2 coefficient larger than one.
2007-07-19 09:43:14
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answer #2
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answered by nasamike2001 2
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Factors of 63: 9, 7; 3, 21; 1, 63
Try 9 and 7:
(x + 7)(-4x + 9)
2007-07-19 09:09:56
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answer #3
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answered by yeeeehaw 5
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initiate by making use of observing the possibles - sixty 3 must be the two -9*-7 or 9*7. -4x² must be -x*4x,-2x*2x or -4x*x. -19 can in ordinary terms be -28+9. then you definitely placed the products mutually continuously examine what you recognize - then the respond is easy.
2016-12-14 13:53:00
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answer #4
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answered by jowers 4
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this one is a 3 bracer
(-1)(4x²+19x-63) Note the sign changes
(-1)(x+7)(4x-9) or
(x+7)(9-4x)
2007-07-19 09:15:48
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answer #5
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answered by 037 G 6
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y = -4x²-19x+63 (I also did this one on the other board for you.)
y = (-4x + 9)(x + 7)
2007-07-19 09:10:57
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answer #6
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answered by Reese 4
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(-4x^+9)(x+7) = -4x^2 - 28x + 9x + 63 = -4x^2 - 19x +63
2007-07-19 09:26:02
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answer #7
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answered by Ayana S. A-J 2
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y=-4x²-19x+63
y= (-4x+9)(x+7)
2007-07-19 09:25:24
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answer #8
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answered by ironduke8159 7
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- (4x² + 19 x - 63)
- (x + 7) (4x - 9)
If desired , may be written as:-
(x + 7) (9 - 4x)
2007-07-20 21:37:35
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answer #9
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answered by Como 7
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(x+7)(-4x+9)
2007-07-19 09:17:57
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answer #10
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answered by nazaryan97 2
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