Factor the polynomial completely. If the polynomial cannot be factored, write prime.
24k3m - 81m4
(6km - 9m2)(4k2 + 9m2)
3m(2k - 3m)(4k2 + 6km + 9m2)
3m(8k - 3m)(k2 + 6km + 9m2)
3m(2k + 3m2)(4k2 - 6km + 9km2)
2007-07-19 08:07:39 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use a formula:
a3 + b3 = (a + b)(a2 – ab + b2)
a3 – b3 = (a – b)(a2 + ab + b2)
24k3m - 81m4
= 3m (8k^3 - 27m^3)
= 3m (2k - 3m)(4k^2 + 6km + 9m^2)
2007-07-19 08:11:34 · answer #1 · answered by Reese 4 · 3⤊ 0⤋
We can first factor out 3m, so
3m(8k^3 - 27m^3)
we use the difference of cubes for 8k^3 - 27m^3
(2k - 3m)(4k2 + 6km + 9m2)
putting all the pieces together, we get
3m(2k - 3m)(4k2 + 6km + 9m2) as the answer
2007-07-19 08:14:44 · answer #2 · answered by kousuke51 2 · 1⤊ 0⤋
24k^3m - 81m^4 =
3m(8k^3 - 27m^3) =
3m[(2k)^3 - (3m)^3] =
3m(2k - 3m)(4k2 + 6km + 9m2).
2007-07-19 08:14:33 · answer #3 · answered by Anonymous · 0⤊ 0⤋
24k3m - 81m4
3m(8k^3-27m^3)
=3m (2k-3m)(4k^2+6km+9m^2)
2007-07-19 08:16:30 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋